{"id":121539,"date":"2026-01-17T04:02:12","date_gmt":"2026-01-17T04:02:12","guid":{"rendered":"https:\/\/www.newsbeep.com\/us-fl\/121539\/"},"modified":"2026-01-17T04:02:12","modified_gmt":"2026-01-17T04:02:12","slug":"no-1-womens-swimming-to-compete-at-home-against-nova-southeastern","status":"publish","type":"post","link":"https:\/\/www.newsbeep.com\/us-fl\/121539\/","title":{"rendered":"No. 1 Women\u2019s Swimming to compete at Home against Nova Southeastern"},"content":{"rendered":"

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\n Story Links
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No. 1 Keiser Women’s Swimming\u00a0team will compete at home against defending Division II National Champion Nova Southeastern on Saturday, January 17. The meet is scheduled to begin at 10:00 a.m at the Lake Lytal Aquatic Center.
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\n\"Meet<\/p>\n

No. 1 Keiser Seahawks vs Nova Southeastern Sharks (Division II)

\nLake Lytal Aquatic Center – West Palm Beach, Fla.

\nSaturday, January 17 at 10:00 PM<\/p>\n

LIVE STATS:\u00a0($) Meet Mobile app

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\n\"series\"
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\n\tAll-time record: 0-8
\n\tLast meet: Keiser\u00a081, NSU\u00a0181\u00a0(Jan. 24, 2025- Fort Lauderdale, Fla.)
\n\tRecord on the road: 0-4 <\/p>\n

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\n\"story\"
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\n\tThe Seahawks are 2-4 in duals this season following their meet against Division II Tampa last week
\n\tKeiser claimed wins in four individual events and won the 100 Medley Relay
\n\tAlanis Santiago<\/a> picked up two wins at the meet, winning the 100 Free and the 500 Free in her debut with KU
\n\tLuiza Bersi<\/a>\u00a0(400 IM)\u00a0and Kate Vorontsova<\/a> (50 Breast) also picked up wins at the meet <\/p>\n

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\n\"event
\n200 Medley Relay
\n1000 Free
\n200 Free
\n100 Back
\n100 Breast
\n100 Fly
\n50 Free
\n100 Free
\n200 Back
\n200 Breast
\n500 Free
\n100 Fly
\n200 IM
\n400 Free Relay<\/p>\n

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\nFor the most up-to-date information about the program, follow Keiser swimming & diving on\u00a0X<\/a>\u00a0and\u00a0Instagram<\/a>\u00a0and like us on\u00a0Facebook<\/a>.
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\nGeneral athletic news can be found at\u00a0KUSeahawks<\/a>\u00a0on Facebook,\u00a0kuseahawks<\/a>\u00a0on Instagram, and\u00a0kuseahawks<\/a>\u00a0on X.<\/p>\n