NEW YORK (AP) \u2014 New Orleans\u2019 DeAndre Jordan won the Twyman-Stokes Teammate of the Year award Wednesday, edging Portland\u2019s Jrue Holiday and Houston\u2019s Jeff Green.<\/p>\n
Jordan finished with 1,445 points in voting by 385 current NBA players. Holiday \u2014 a three-time winner \u2014 finished with 1,437 points and Green had 1,420.<\/p>\n
A panel of league executives selected 12 finalists, six from each conference, to be considered for the honor. Jordan adds the award to a list of accolades that includes three All-NBA selections, two All-Defensive Team picks, one All-Star nod, an Olympic gold medal from the 2016 Rio de Janeiro Games and a championship with Denver in 2023.<\/p>\n
The award pays tribute to the player deemed the league\u2019s best teammate \u201cbased on selfless play, leadership on and off the court as a mentor and role model to other NBA players, and commitment to the team.\u201d<\/p>\n
It has been presented since 2013 and is named for Jack Twyman and Maurice Stokes, teammates on the Rochester\/Cincinnati Royals from 1955-58. Stokes suffered a brain injury in the final game of the 1957-58 regular season, fell into a coma days later and was paralyzed. Twyman became Stokes\u2019 legal guardian and advocate, and supported him for the rest of his life.<\/p>\n
Other players nominated for the award this season were Toronto\u2019s Garrett Temple, Charlotte\u2019s Pat Connaughton, New York\u2019s Jalen Brunson, Boston\u2019s Jayson Tatum, San Antonio\u2019s DeAaron Fox, Detroit\u2019s Duncan Robinson, Oklahoma City\u2019s Jaylin Williams, Orlando\u2019s Desmond Bane and the Los Angeles Lakers\u2019 Marcus Smart.<\/p>\n
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